0=3x^2+9x+2

Solution for 0=3x^2+9x+2 equation:

0=3x^2+9x+2

We move all terms to the left:

0-(3x^2+9x+2)=0

We add all the numbers together, and all the variables

-(3x^2+9x+2)=0

We get rid of parentheses

-3x^2-9x-2=0

a = -3; b = -9; c = -2;
Δ = b2-4ac
Δ = -92-4·(-3)·(-2)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{57}}{2*-3}=\frac{9-\sqrt{57}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{57}}{2*-3}=\frac{9+\sqrt{57}}{-6}
$